12x^2-68x-244=0

Solution for 12x^2-68x-244=0 equation:

12x^2-68x-244=0

a = 12; b = -68; c = -244;
Δ = b2-4ac
Δ = -682-4·12·(-244)
Δ = 16336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16336}=\sqrt{16*1021}=\sqrt{16}*\sqrt{1021}=4\sqrt{1021}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-68)-4\sqrt{1021}}{2*12}=\frac{68-4\sqrt{1021}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-68)+4\sqrt{1021}}{2*12}=\frac{68+4\sqrt{1021}}{24}
$